Which method would you use in Python to create a new copy of a list?

Which method would you use in Python to create a new copy of a list?

• A. copy()
• B. slice()
• C. duplicate()
• D. replicate()

Answer: (B)

The appropriate method to create a new copy of a list in Python is known as slicing. By using slicing, you can create a new list that is a copy of the original list by simply specifying the slice with the colon operator. For example, if you have a list named `my_list`, you can create a new list that is a copy of it by writing `new_list = my_list[:]`. This action generates a shallow copy, meaning that changes made to the new list will not affect the original list, provided that the elements are immutable. The other options, while they may sound plausible, do not exist as standard methods for duplicating a list. There is a method called `copy()` available through the list object, which does allow you to create a shallow copy of the list, and may lead to confusion if considered. However, it is important to note that slicing is a more commonly used and versatile approach among Python developers for this purpose.

The appropriate method to create a new copy of a list in Python is known as slicing. By using slicing, you can create a new list that is a copy of the original list by simply specifying the slice with the colon operator. For example, if you have a list named my_list, you can create a new list that is a copy of it by writing new_list = my_list[:]. This action generates a shallow copy, meaning that changes made to the new list will not affect the original list, provided that the elements are immutable.

The other options, while they may sound plausible, do not exist as standard methods for duplicating a list. There is a method called copy() available through the list object, which does allow you to create a shallow copy of the list, and may lead to confusion if considered. However, it is important to note that slicing is a more commonly used and versatile approach among Python developers for this purpose.